Visualize the hash map approach to checking if two strings are anagrams.
Two strings are anagrams if one is a rearrangement of the other. The hash map approach counts character frequencies in S, then decrements for each character in T. If all counts reach zero, they are anagrams.
Iterate through string S. For each character, increment its count in the frequency map.
Iterate through string T. For each character, decrement its count. If a count goes below zero or the character is missing, return false.
If all frequency map entries are zero after processing T, the strings are anagrams. Time: O(n), Space: O(n).